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DaleSeo
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Mar 11, 2026
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풀이 제출해 주셔서 감사합니다! 다른 참여자 분들처럼 작성하신 코드의 시간/공간 복잡도를 구해서 주석으로 표시해보시면 어떨까요?
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| for letter in t: | ||
| if letter not in char_count: | ||
| char_count[letter] = 1 | ||
| else: | ||
| char_count[letter] += 1 |
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파이썬 사전의 get() 함수를 활용하시면 코드가 좀 더 간결해질 것 같습니다.
(참고: https://daleseo.com/python-dictionary/)
Suggested change
| for letter in t: | |
| if letter not in char_count: | |
| char_count[letter] = 1 | |
| else: | |
| char_count[letter] += 1 | |
| for letter in t: | |
| char_count[letter] = char_count.get(letter, 0) + 1 |
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