any_or_all.py

# any()

# This expression returns True if any element of the iterable is true. 
# If the iterable is empty, it will return False.

# Code

# >>> any([1>0,1==0,1<0])
# True
# >>> any([1<0,2<1,3<2])
# False
# all()

# This expression returns True if all of the elements of the iterable are true. If the iterable is empty, it will return True.

# Code

# >>> all(['a'<'b','b'<'c'])
# True
# >>> all(['a'<'b','c'<'b'])
# False
# Task

# You are given a space separated list of integers. If all the integers are positive, then you need to check if any integer is a 
# palindromic integer.

# Input Format

# The first line contains an integer N. N is the total number of integers in the list. 
# The second line contains the space separated list of N integers.

# Constraints
# 0 < N < 100

# Output Format

# Print True if all the conditions of the problem statement are satisfied. Otherwise, print False.

# Sample Input

# 5
# 12 9 61 5 14 
# Sample Output

# True

# Explanation

# Condition 1: All the integers in the list are positive. 
# Condition 2: 5 is a palindromic integer.

# Hence, the output is True.

# Problem's link: https://www.hackerrank.com/challenges/any-or-all #

n = raw_input()
nums = raw_input().strip().split()

print all(int(x) > 0 for x in nums) and any(x == x[::-1] for x in nums)