syllable_counter

from pattern.en import tokenize

def syllable_counter(string):
	""" Takes a word, and evaluates (roughly)
		the number of syllables it contains.
		This function returns number of syllables
		There must be a space after the string,
		otherwise it will break
		>>> syllable_counter('mouse ')
		1
		>>> syllable_counter('a ')
		1
	"""
	i = 0 # index of while loop 
	counter = 0 # counter of syllables
	vowels = ['a','e','i','o','u','y','e '] # what are vowels
	diphthongs = ['ee', 'ei', 'ea', 'oo', 'oi', 'oy', 'ou', 'ai', 'ie'] #what are diphthongs
	index = 0 

	while string[index] != ' ': # break at space
		char = string[index] # look at each letter in string
		next_char = string[index+1] # and the letter following

		if char in vowels: 
			if (char + next_char in diphthongs): 
				counter = counter + 1 # count
				index = index + 1 # skips second letter in diphthong
			elif (char == 'e' and next_char == ' '): # assume if e at end of word, is not syllable
				pass # don't count
			else: 
				counter = counter + 1 # if it's a solitary vowel, add one to counter

		index = index + 1

	return counter

def sentance_strip(text):
	#remove junk
	#junk is puncturation 
	# and 


def sentance_eval(sentance):
	""" Takes a sentance, and evaluates
		the number of syllables contained in 
		each word. This function returns number of syllables
		There must be a space after the string,
		otherwise it will break
		>>> sentance_eval('Im a mouse ')
		3
		>>> syllable_counter('She is alone ')
		4
	"""
	sentance_as_list = sentance.split()  # make list of strings (words) 
	sentance = [word + ' ' for word in sentance_as_list] #now with spaces so it works in syllable_counter
	counter = 0
	for word in sentance:
		counter += syllable_counter(word) 
	return counter

print sentance_eval('a very long time')

# if __name__ == "__main__":
# 	import doctest
# 	doctest.testmod()
# 	doctest.run_docstring_examples(syllable_counter, globals(),verbose = True)